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	<title>Comments on: For recent Major League Baseball and National Football League season, three baseball tickets and two football?</title>
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	<link>http://www.truesportsblog.net/1279/for-recent-major-league-baseball-and-national-football-league-season-three-baseball-tickets-and-two-football/</link>
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		<title>By: Steve M</title>
		<link>http://www.truesportsblog.net/1279/for-recent-major-league-baseball-and-national-football-league-season-three-baseball-tickets-and-two-football/comment-page-1/#comment-8630</link>
		<dc:creator>Steve M</dc:creator>
		<pubDate>Fri, 13 Nov 2009 04:58:53 +0000</pubDate>
		<guid isPermaLink="false">http://www.truesportsblog.net/1279/for-recent-major-league-baseball-and-national-football-league-season-three-baseball-tickets-and-two-football/#comment-8630</guid>
		<description>Each Baseball Ticket cost 11.19 and football 35.74

Basically Have x=Baseball ticket and y=football ticket
 3x+2y=105.05
+2x+y=58.12
--------------------
5x +3y =163.17-&gt; which is y=(163.17-5x)/3

Fill y in for one equation to solve for x

then enter x in the equation to solve for y</description>
		<content:encoded><![CDATA[<p>Each Baseball Ticket cost 11.19 and football 35.74</p>
<p>Basically Have x=Baseball ticket and y=football ticket<br />
 3x+2y=105.05<br />
+2x+y=58.12<br />
&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<br />
5x +3y =163.17-> which is y=(163.17-5x)/3</p>
<p>Fill y in for one equation to solve for x</p>
<p>then enter x in the equation to solve for y</p>
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